2n+3/8n^2+4+n-3/8n^2+4n - solution

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Solution for 2n+3/8n^2+4+n-3/8n^2+4n equation:

n in (-oo:+oo)

(3/8)*n^2-((3/8)*n^2)+2*n+n+4*n+4 = 0

(3/8)*n^2+(-3/8)*n^2+2*n+n+4*n+4 = 0

7*n+4 = 0 // - 4

7*n = -4 // : 7

n = -4/7

n = -4/7

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